亚洲免费乱码视频,日韩 欧美 国产 动漫 一区,97在线观看免费视频播国产,中文字幕亚洲图片

      1. <legend id="ppnor"></legend>

      2. 
        
        <sup id="ppnor"><input id="ppnor"></input></sup>
        <s id="ppnor"></s>

        Oracle中檢查外鍵是否有索引的SQL腳本分享

        字號(hào):


            代碼如下:
            COLUMN COLUMNS format a30 word_wrapped
            COLUMN tablename format a15 word_wrapped
            COLUMN constraint_name format a15 word_wrapped
            SELECT TABLE_NAME,
            CONSTRAINT_NAME,
            CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
            NVL2(CNAME3, ',' || CNAME3, NULL) ||
            NVL2(CNAME4, ',' || CNAME4, NULL) ||
            NVL2(CNAME5, ',' || CNAME5, NULL) ||
            NVL2(CNAME6, ',' || CNAME6, NULL) ||
            NVL2(CNAME7, ',' || CNAME7, NULL) ||
            NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
            FROM (SELECT B.TABLE_NAME,
            B.CONSTRAINT_NAME,
            MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
            MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
            MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
            MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
            MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
            MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
            MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
            MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
            COUNT(*) COL_CNT
            FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
            SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
            SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
            POSITION
            FROM USER_CONS_COLUMNS) A,
            USER_CONSTRAINTS B
            WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
            AND B.CONSTRAINT_TYPE = 'R'
            GROUP BY B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
            WHERE COL_CNT > ALL
            (SELECT COUNT(*)
            FROM USER_IND_COLUMNS I
            WHERE I.TABLE_NAME = CONS.TABLE_NAME
            AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
            CNAME6, CNAME7, CNAME8)
            AND I.COLUMN_POSITION <= CONS.COL_CNT
            GROUP BY I.INDEX_NAME)
            /
            在上面的基礎(chǔ)上修改了一下,可以檢查所有的用戶。
            代碼如下:
            SET linesize 400;
            COLUMN OWNER format a10 word_wrapped
            COLUMN COLUMNS format a30 word_wrapped
            COLUMN TABLE_NAME format a15 word_wrapped
            COLUMN CONSTRAINT_NAME format a40 word_wrapped
            SELECT OWNER,
            TABLE_NAME,
            CONSTRAINT_NAME,
            CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||
            NVL2(CNAME3, ',' || CNAME3, NULL) ||
            NVL2(CNAME4, ',' || CNAME4, NULL) ||
            NVL2(CNAME5, ',' || CNAME5, NULL) ||
            NVL2(CNAME6, ',' || CNAME6, NULL) ||
            NVL2(CNAME7, ',' || CNAME7, NULL) ||
            NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS
            FROM (SELECT B.OWNER,B.TABLE_NAME,
            B.CONSTRAINT_NAME,
            MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,
            MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,
            MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,
            MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,
            MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,
            MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,
            MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,
            MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,
            COUNT(*) COL_CNT
            FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,
            SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,
            SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,
            POSITION
            FROM DBA_CONS_COLUMNS WHERE OWNER NOT IN ('SYS','SYSTEM','SYSMAN','HR','OE','EXFSYS','DBSNMP','MDSYS','OLAPSYS','SCOTT','EXFSYS','SH','PM','CTXSYS')) A,
            DBA_CONSTRAINTS B
            WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME
            AND B.CONSTRAINT_TYPE = 'R'
            GROUP BY B.OWNER,B.TABLE_NAME, B.CONSTRAINT_NAME) CONS
            WHERE COL_CNT > ALL
            (SELECT COUNT(*)
            FROM DBA_IND_COLUMNS I
            WHERE I.TABLE_NAME = CONS.TABLE_NAME AND I.TABLE_OWNER=CONS.OWNER
            AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,
            CNAME6, CNAME7, CNAME8)
            AND I.COLUMN_POSITION <= CONS.COL_CNT
            GROUP BY I.INDEX_NAME)
            /